2x^2-8=2330

Solution for 2x^2-8=2330 equation:

2x^2-8=2330

We move all terms to the left:

2x^2-8-(2330)=0

We add all the numbers together, and all the variables

2x^2-2338=0

a = 2; b = 0; c = -2338;
Δ = b2-4ac
Δ = 02-4·2·(-2338)
Δ = 18704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18704}=\sqrt{16*1169}=\sqrt{16}*\sqrt{1169}=4\sqrt{1169}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1169}}{2*2}=\frac{0-4\sqrt{1169}}{4}
=-\frac{4\sqrt{1169}}{4}
=-\sqrt{1169}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1169}}{2*2}=\frac{0+4\sqrt{1169}}{4}
=\frac{4\sqrt{1169}}{4}
=\sqrt{1169}
$